Number System Sample Question Practice Exercise For Quiz and Assignment or home work
Digits of different number systems are given below:
Base 32
|
Base 24
|
Base 16
|
Base 10
|
0
|
0
|
0
|
0
|
1
|
1
|
1
|
1
|
2
|
2
|
2
|
2
|
3
|
3
|
3
|
3
|
4
|
4
|
4
|
4
|
5
|
5
|
5
|
5
|
6
|
6
|
6
|
6
|
7
|
7
|
7
|
7
|
8
|
8
|
8
|
8
|
9
|
9
|
9
|
9
|
A
|
A
|
A
|
|
B
|
B
|
B
|
|
C
|
C
|
C
|
|
D
|
D
|
D
|
|
E
|
E
|
E
|
|
F
|
F
|
F
|
|
G
|
G
|
||
H
|
H
|
||
I
|
I
|
||
J
|
J
|
||
K
|
K
|
||
L
|
L
|
||
M
|
M
|
||
N
|
N
|
||
O
|
|||
P
|
|||
Q
|
|||
R
|
|||
S
|
|||
T
|
|||
U
|
|||
V
|
Q1. 4.5
Marks
Solve this question without converting the numbers into Base
10
a.
Convert (1110)2 to base-8
001 110
(16)8
b.
Convert (10000101110)2 to base-16
0100 0010 1110
(42E)16
c.
Convert (1111100000111010101)2 to
base-32
01111 10000 01110
10101
(FGEL)32
Q2. 4.5
Marks
a.
Convert (123)9 to base-10
1x92 + 2x91 +
3x90 = 81 + 18 + 3 = (102)10
b.
Convert (12)32 to base-16
1x321 + 2x320 = 32 +
2 = (34)10
34 ÷ 16: quotient = 2, remainder = 2
2 ÷ 16: quotient = 0, remainder = 2
Answer: (22)16
c.
Convert (15)10 to binary
15 ÷ 2 =
quotient
|
Remainder
|
|
15
÷
2
|
7
|
1
|
7
÷
2
|
3
|
1
|
3
÷
2
|
1
|
1
|
Answer: (1111)2
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