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Swap two Number without using temporary variable in C++ Code





Write a ‘void’ function that swaps two numbers but does not use any local variables that are other than the ones declared as formal parameters?

void swap_func(int& num1, int& num2)
{
num2=num1+num2;
num1=num2-num1;
num2=num2-num1;
return;
}
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  • Title : Swap two Number without using temporary variable in C++ Code
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  • Date : 11:40
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